WINNER OF DRAWING FROM Spring '04 QUIZ:
ELLERY POTASH '75 (EE) '78 (MS)
Correct respondents answered "more than 1000 AA cells" to the question "If the average human adult were battery powered, how many AA cells would it take to power a person for one day?"
Kazimierz (Kai) Siwiak '70 '72 (EE), who submitted the question, began with the energy in an AA cell (1.3V)x(1400/1000A)x(3600sec/hour) = 6552 joules or 1556 calories, at 4.184 joules per calorie. The basal metabolic rate for an adult is about 1500-1600 food calories per day. The twist in this problem is that one food calorie is 1000 calories. It would require at least 1000 AA cells to power a typical resting adult for a day. Professor Henry Bertoni '62 (EE) '68 (EL) agreed, saying that a person generates as much heat as a 100 watt light bulb in a day, that is 2400 watt-hours. The AA cell can deliver 1.4 x 1.3 = 1.8 watt-hours of energy. Hence, it takes 2400/1.8 = 1333 AA cells to power a person for one day.
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WINNER OF DRAWING FROM WINTER '04 QUIZ:
HILDING OLSON `59.
Correct respondents answered "1.5 miles per hour" to the question posed Professor Emeritus Robert Ackerberg about a river`s current speed that had separated a rower from his fallen hat. They realized you need to eliminate the effect of the moving stream, which affects both the hat and the rower, and take as your reference the hat. If it took the rower 20 minutes to reach the hat, it must have also taken him 20 minutes to row away from the hat before realizing he dropped it and turning around. Therefore, the rower was separated from the hat by 2 x 20 minutes = 40 minutes. In this time, the hat floated one mile from the bridge where the rower dropped it, due entirely to the current, and so the current speed is 1/40 mile per minute = 1.5 miles per hour.
Therefore, he was separated from the hat by 2 x 20minutes = 40 minutes. In this time, the hat floated one mile from the bridge, due entirely to the current, and so the current speed is 1/40 mile per minute = 1.5 miles per hour.
Other people who answered the quiz question correctly:
George F. Abrantes `80
Robert Andrejczyk
Murray Applestein `73
Preston Augenbaum `64
John Barbieri
Melvin Benjamin `62 `70
Seymour Friedman `71
Arthur Glassman `54 `56
Walter Heinz `86
Dan Hittner `91
Everett Joline `55 `73
Richard J. Kapash `66 `69
David R. Kilanowski `73
Tina Liu `95
Seyed Michael Henry Mansourbeigi `93 `98
Bruce Merdjan `92
John J Mineo `57
Stanley Nathanson `83
James Pavlides `66
Gary Petschauer, `71
Robert M Porter `66
Richard Rizza `83 `87
Rogard Ross `88
Nigel Salts `82
Robert J. Sanator `51
Steve Strauss `75
Howard Teich `61
Will Toppin `78
Robert Trentacoste `72
G.C. (Mona) Vaghasia
Jonas Verdeflor `04
Chui-Mei Wong `03
David A. Zuckerberg `68
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WINNER OF DRAWING FROM FALL '03 QUIZ:
Salvatore Rea '77.
Salvatore Rea correctly answered 621 degrees Fahrenheit to the question Robert L. Wolke `49 (CH) posed from his book What Einstein Told His Barber: More Scientific Answers to Everyday Questions: "What temperature is `twice as hot` as 80 degrees Fahrenheit?" stumped many alumni. Correct respondents realized that you need to double the heat, not the temperature. To do that, you need to convert the Fahrenheit number to Celsius, then to Kelvin, which uses a scale of numbers where zero means no heat at all; double that Kelvin number to get twice the heat and convert it back to Celsius and then to Fahrenheit. So, 80 degrees Fahrenheit = 27 degrees Celsius = 300 Kelvins x 2 = 600 Kelvins = 327 degrees Celsius = 621 degrees Fahrenheit.
Other people who answered the quiz question correctly:
Martin S. Abelow `56
Melvin Benjamin `62 `70
Joseph Berchielli `68
Jamie K. Brown `77
Michael Coyle `93 `94
Richard Ferrara `97 `99
Carl Frey `84
Chris Fry `66
Art Glassman `54 `56
Robert W Kiefer Jr. `92
Gordon Kraeger `44
Edward Kush `64
Michael J. Lerman `59
George C. L`Heureux
Harvey V. Lilenfeld `66
Simon Lu
Robert J. Mackey `84 `88
Susan McCoy `02
John Mineo `57
Richard Persichilli
Ellery Potash `75 `78
John J. Prizzi `74
Salvatore Rea `77
Richard Rizza `83 `87
Herb Schiller `65 `73
Joseph Schuchman `79
Barry S. Schwartz `67 `68
Victor H. Seliger `48 `51
Marc Shapiro `64
Andrew M. Shooman `92
Kazimierz Siwiak `70 `72
Oscar Weber `61 `66
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WINNERS OF DRAWING FROM SUMMER '03 QUIZ:
John J. Fortin '81
Robert Trentacoste '72.
Fortin and Trentacoste correctly answered 52.5 minutes to the problem posed by Professor Emeritus Robert Ackerberg: A wealthy man goes to work each morning, driven by his chauffeur to a ferry. When the man returns from work in the late afternoon, the chauffeur leaves the house at the right time to meet the ferry as it docks. One day, the man decides to take a ferry that leaves one hour earlier than his usual ferry. When the ferry docks, his chauffeur is not there and he begins to walk home. Eventually, the chauffeur meets him on the road and drives him back home, where they arrive 15 minutes earlier than usual. How many minutes was the man walking along the road?
Solution: Imagine you are the chauffeur. If you arrived home 15 minutes earlier than usual, you must have been 7.5 minutes from the dock when you met up with your employer, because if you drove 7.5 minutes to the dock and 7.5 minutes back to the place where you met your employer, you would have arrived home at the same time as usual. Therefore, your employer must have been walking for 52.5 minute (60 minus 7.5 equals 52.5), because if you had driven all the way to the dock in 7.5 minutes, it would have been an hour later.
Other people who answered the quiz question correctly:
Martin S. Abelow '56
Herman Altman '50
Murray Applestein '73
John Barbieri '44 '53 '63
William I. Berks '51 '53
Howard S. Bertan '63
Francis Boesch '57
Robert Breuer '57
Carl F. Buhrer
Sandy Camacho '84
Peter Chan '89 '85
Ping Sun Chun '64
Eva H. Helfman Cogan '75
Sam S. Cohen '81
Michael Coyle '93 '94
Ronald J. Desmond '52
Louis Divone '55
Paul Farrar
Alfred E. Feuersanger '57
Norman Fine '54
Robert Frankel '60 '63
Harry Friedenreich '53
Craig M. Garretson '53
Li Geng
Ernest J. Gerbitz '94
Theodore Givand '60
Tonto Goldberg
Jerold Green '90
Yan Gulko '93
Everett S. Joline '55 '73
Franklin Kemp '65 '67
Sheldon Kinbar '61
Mike Laufer '53
Daniel LaVietes '63
Edward Leff '60 '62
George C. L'Heureux
Harvey V. Lilenfeld '66
Tina D. Liu '95
Dhema Mahajan '73
Seyed Michael
Henry Mansourbeigi '93 '98
Jay Martin '78 '81
Carlos Mejia '97
Richard Mishelof '63
John Musante '93
Victor J. Musante '61 '69
Yat Cheung Ng '91
Hilding M. Olson '59
James Pavlides '66
Rich Persichilli '87
Angela Bellivan Pettinelli '83
Gary S. Popkin '87
Robert Prener '69
Sam Rimawi '88
Richard Rizza '83 '87
Dino L. Roman '81 '83
Dominick J. Romano '60
Arnold Rosenthal '58
Lou Rostand '64
Tom Scacco '66
Ben Schneidman '71
Allen H. Schwartz '57
Victor H. Seliger '48 '51
John Shaughnessy '82
Joseph Sinniger '59 '61
Michael B. Stein '70
Michael Stoiko '51
Howard I. Teich '62
Neil D. Weiser '73
Robert Wurtz '72
Tanya Yaroslavskaya
Yuriy Yaroslavskiy '98
Alex Zarenin '92 '98
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WINNERS OF DRAWING FROM SPRING '03 QUIZ:
Lawrence R. Brecker '62
Peter Lau '93
David Santee '81.
The following people correctly answered the question posed by Howard Beroff '59: What do you do if an airline has a rule that it will not accept luggage measuring more than 100 cm in any one dimension, and you want to check a fishing rod that measures 170 cm in length? (And, no, you cannot fold the rod.)
Answer: Get a cubic box measuring 100 cm and place the fishing rod into it diagonally. A cubic box 100 cm per side has a diagonal of 173 cm, more than enough to accommodate a 170 cm fishing rod. (and maybe some bait!)
Other people who answered the quiz question correctly:
George Abrantes '80
Robert Ackerberg
Philip Barish
Lawrence R. Brecker '62
Clifton J. Callahan '54 '62 '71
Frank Cannata '86
Chris Carbuto '95
Charlie Casazza '61
Hin Kan Chan '87
David J. Chays '98
Joel Chesler '66 '67
Eduguardo Coppola '97
George A. Cole '67
Joe Colgan '51
Michael F. Coyle '93, '94
Jean Develet '53 '54
Dennis DiMaria '98
Nigel Elias '81
Lawrence Edelman '58
Robert E. Feldman '69
Robert Ferraglio '69
Richard Ferricane '67
Jim Garofalo '80
Bernard Gollomp '49
Jerome T. Helfgott '43
Gene Holzer '52
Donald Hom '89
Bonitto Housen '99
Lawrence F. Hughes '89
Howard Jaslow '56
Richard Kaufmann '74
Kenneth B. Keating '53 '55
Mike Kornely '49
Ron Kryger '62
Jeff Kushin '70
Peter Lau '93
Watts W. Lawrence '46
Ming Li '84
Seyed Michael
Henry Mansourbeigi '93 '98
Abraham S. Mantell
Irwin M. Marson '53
Vincent Martella '66
George Martin '72
Leopold May '51
Carlos Mejia '97
Richard Mishelof '63
Yihia R. Mohammand '95
Koi Morris '94
Louis A. Mulieri '58
Peter Nicholakakos '53
John O'Donohue '56
Hilding M. Olson '59
Rich Persichilli '87
Sridhar Ramaswamy '88
David Rice '55
Richard Rizza '83 '87
John Rodolico '72
Louis E. Rostand '64
David Santee '81
Anubhav Savant
Herb Schiller '65 '73
Joseph Schuchman '79
Richard Schulkind '74
Richard Seegull '94
Gary Selsky '73 '75
Abraham Siegel '48
Kazimierz Siwiak '70 '72
Lowell Smilen '62
Steve Steckler '67
Bennet Strauss '86
Steve A. Strauss
Eugene Vaynshteyn '02
Horton Wasserman '57
Oscar W. Weber '61 '66
Paul G. Weiner '60
Allan Weinstein '61
William F. Widulski
William K. Woll '61
Albert A. Yetman '59
Andrew E. Zeger '64
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WINNER OF DRAWING FROM WINTER '03 QUIZ:
Daniel Sommer '85 '88.
The following people correctly answered 2.7 degree Kelvin
(-454 degrees Fahrenheit) to the question: If you could measure the temperature in a deserted region of outer space, with nothing for light years around, how cold would it be?
Other people who answered the quiz question correctly:
Robert Ackerberg
Michael F. Coyle '93
Harold Gainer '58
Francis M. Grant '59
Richard A. Kaufmann '74
Ming Lam '96 '00
Frank Lin '85
Herbert H. Lipowsky '66 '68
Robert J. Mackey '84 '88
Seyed Michael Henry Mansourbeigi '93 '98
Abraham S. Mantell
Vincent Martella '66
Joe Milstein '71
John J Mineo '57
MeeLing Moy '97
John Musante '93
Robert Prener '69
James D. Redding Jr., PE, '53
Herb Schiller '65 '73
Joseph C. Schuchman '79
Kai Siwiak '70 '72
Herb Strohsahl '82
Anthony E. Vizioli '76
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WINNER OF DRAWING FROM FALL '02 QUIZ:
Alwyn D'Sa '80.
More than 90 people correctly answered the question: What is the shortest distance from point A to point B traveling on the surface of a cube.
Answer: The shortest path is a straight line when the cube is unfolded. Hence, the length is square root of AD2 + DB2 = square root of 4 + 1 = square root of 5 = 2.23606797.
Other people who answered the quiz question correctly:
Robert Ackerberg
Dorothy Adams
Murray L. Applestein '73
Robert Archer '50
Paul C Aspinwall '93
Paul Basile '88 '89
Robert L. Beer '41
Steven Block '65
Ed Bobroff '40
Francis T. Boesch '57 '60 '63
Mario Calvache '77
Dennis Chamot, '64
Ken Kohn Che '70
John Chino '71
George A. Cole '67
Edward M. Coppola '97
Michael F. Coyle '93 '94
Joseph P. Crosson '71 '75
Attilio A. DeMeo '44
Edward A. Destremps '52
Sunny Eng '87
Leo M. Esnes '81
Alfred E. Feuersanger '57
Hubert Figueiredo '80
Jerry Flynn '69 '71
Jorge E. Fontes '92
Richard P. Fornari '61
Sy Friedman '72
Norma and Harold Gainer '58
Ernest J. Gerbitz '94
Roger Gilmont '43 '47
Salvatore Giordano '51
Shelly Gordon '63
Steve Grivas '82
Boas Grossman '98
Lawrence J. Hahn '52 '62
Richard K. Hall '65
Bill Heinz '60 '62
Jerome Helfgott '43
Thaddeus L. Hoffa '66
Gene Holzer '52
Doug Hong '87
Richard Kaufmann '74
George Kellinger '52
Sheldon Kinbar '61
Gordon W. Kraeger '44
John M. Lass '70
Norman W. Lord '44
Elizabeth Maas '78
Dhema Mahajan '73
Seyed Michael Henry Mansourbeigi '93 '98
Abraham S. Mantell
Harvey Marks '55
Vincent Martella '66
Jelena Matic '98 '01
Frank C. Mauro '76
Larry Miller '59 '62 '85
Yihia R. Mohammad '95
Koi M. Morris '94
Evans Mountzouris '75 '79
Ilya Nazarov
David Negrin '51 '55
Henry Ngo
Stephen A. Ohayon '69
James Pavlides '66
Richard Persichilli '87
Frederick T. Rey '63
Lou Rostand '64
Irving Rozansky '59
Bernard Salzberg '29 '33 '41
George Sau '76
Tom Scacco '66
Igor A. Schtein
Michael Schulz '94
Gene Schwartz '70 '73
Gary Selsky '73 '75
Howard Shore '85
Martin Siegel '64 '67
Sri K. Sinha '78
Kai Siwiak '70 '72
Brad Solomon '80
Daniel Sommer '85 '88
Hyman Strell '68
Scott I. Taylor '95
Igor Teplitskiy '97
Peter Theophall '64
Manny Torres '85
Robert Trentacoste '72
Neil Wotherspoon '52 '57
Michael Yackavage '87 '02
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WINNER OF DRAWING FROM SUMMER '02 QUIZ:
Ming Lam '96 '00.
More than a dozen people figured the correct answer of Kola Peninsula, Russia, to the question: Where is the world's deepest man-made hole?
Other people who answered the quiz question correctly:
Robert Ackerberg
Tim Atchison `83 `87
Vinny DiGiovanni `65
Francois Frochaux `73
Mike Horowitz `66 *
Felix Khazin `02
Seyed Mansourbeigi `93 `93 `98
Abraham S. Mantell
Julie Ruth '86
Herb Schiller `65
Fred Schmidt `60
Barry Schwartz '67
Daniel Sommer `85 `88
Ross Whiting
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WINNER OF DRAWING FROM SPRING '02 QUIZ:
HAROLD G. SEER '55.
More than two dozen people figured the correct answer of to the question posed by John Pertessis '85: How would you determine which one of the two circuits shown below is inside the black box? Only two wires are available for you to make the determination.
Answer: Circuits 1 (Thevenin) and 2 (Norton) are equivalent circuits. The simplest way to determine which circuit is in the box is to measure heat dissipation. If the box is cool, it contains circuit 1 (which dissipates nothing when undisturbed). If it's hot, the box is circuit 2 (which dissipates 10 kilowatts when undisturbed).
Tom Acquaviva '62
Nunzio Bellini '59
Richard Bertolino '61
Jonathan Corbett
Paul Daitch '60
Tulllio De Filippis '57
Jean A. Develet '53 '54
Gerry Dorman '62
Marc S. Frankel '84
William Galati '62
Salvatore Giordano '51
Bob Grenyo '73
William J. Haneman '51
William W. Heinz '60 '62
Ken Hodge '56
Richard LaRosa '47 '53
Michael J. Loudis '80
Seyed Michael Henry Mansourbeigi '93 '98
Irwin M. Marson '53
Robert Mauro '62 '64 '68
John G. McCullough '67
Richard J. Mohr '57
Louis A. Mulieri '58
James Pavlides '66
Martin D. Reinish '52
Barry Schwartz '67
Vic Seliger '48 '51
Marc Shapiro '64
Kazimierz (Kai) Siwiak '70 '72
Frank Tanzi '85 '89
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WINNER OF DRAWING FROM WINTER '02 QUIZ:
SALVATORE GIORDANO '51
More than 30 people figured the correct answer of Hans Christian Orsted (or Oersted) to the question: The cgs units of magnetic field strength is named after which scientist?
Robert Ackerberg
Dennis Chamot '64
Vera Peshchansky Cherepinsky '98 '99
Gary Eisenhuth '79
Alfred E. Feuersanger '57
Ernest J. Gerbitz '94
Salvatore Giordano '51
Arthur Glassman '54 '56
Tonto Goldberg
Roger Grice '64
Lawrence F. Hughes '89
Richard A. Kaufmann '74
Ming Lam '96 '00
Sam Levine '50 '51
Richard N. Mishelof '63
Donald G. Morin '57
James Pavlides '66
Alan I. Pearlman '75
Herman Rutner '63 '66
Thomas G. Scacco '66
Herb Schiller '65 '73
Raymond W. Schlachter '69
Wolfgang Schubler '71
Richard Seegull '94
Vic Seliger '48 '51
Gary M. Selsky, '73 '75
Jeffrey Shapiro '01
Jim Simes '61
Daniel Sommer '85 '88
Igor Tamopolsky '88
Igor I. Teplitskiy '97
Manny Torres '85
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WINNER OF DRAWING FROM FALL '01 QUIZ:
RICHARD FERRARA '97 '99
More than 85 people figured the correct answer of 87912 to the question: If you substitute numerical digits (but not 0) for the following letters, ABCDE x 4 = EDCBA, what do you get?
Robert Ackerberg
James A. Arida '59 '72
Paul C. Aspinwall '93
Robert Cardone '71
Dennis Chamot '64
Vera Peshchansky Cherepinsky '98 '99
Wai Leung Cheung '01
John Chino '71
Jim Christophersen '70
Joan Davis '84
Dennis L. DiMaria '98
Galo L. Donggilio '97
David Doucette, '68 '70 '74
William Dougherty '34
Thomas W. Eddy '68
Lawrence Edelman '58
Gary Eisenhuth '79
Isaac W. Feinberg '45
Richard Ferrara '97 '99
Albert Feuer '70
Alfred E. Feuersanger '57
Hal Forstrom '50
Eric Fruchtnis '98
Harold Gainer '57
Joe Gencorelli '82 '85
Ernest J. Gerbitz '94
Rebecca Gillman '00
Salvatore Giordano '51
Arthur Glassman '54 '56
Tonto Goldberg
Jules Gommi '61
Eric Herz '52
Mark S. House '85
Lawrence F. Hughes '89
Eric B. Humphrey '83
Suryanarayana Jonnalagadda '97
Richard A. Kaufmann '74
Frederick C. Kuebler '49 '53
Norris L. Larrymore '69
David P. Lashinsky '84 '87
Ira R. Lashinsky '81 '87
John M. Lass '70
Sam Leong '72
Sam Levine '50 '51
Wei Feng (Benny) Lin '01
Mikhail Malamud '96
Seyed M.H. Mansourbeigi '93 '98
Harvey Marks '55
Vincent N. Martella '66
David Mermelstein
John Mineo '57
Richard N. Mishelof '63
Yihia R. Mohammad '95
Irwin W. Moskowitz '61
Ilya Nazarov '04
Marvin Nekrich '75
Kam H. Ng '79
Victor Ofori '64
Henry A. Ovalle '98
Naray Palaniappan '98
James Pavlides '66
John Pertessis '85
Larry Reccoppa '95
Martin S. Roden '63 '65
Marvin Rosado '01
Herman Rutner '63 '66
Thomas G. Scacco '66
John P. Schaefer '55
Herb Schiller '65 '73
Raymond W. Schlachter '69
Fred Schmidt '60
Wolfgang Schubler '71
Richard Seegull '94
Vic Seliger '48 '51
Jeffrey N. Shapiro '00
Howard D. Shore '85
Michael L. Silverman '56 '63
Daniel Sommer '85 '88
Henry Stalzer '62 '69
Warren Sze '88
Igor Tamopolsky '88
Anthony Taverna '67
Igor I. Teplitskiy '97
Robert A. Trentacoste '72
Tania A. Turzer '96
Marie C. Vincent
Neil Weinstein '69
Michael Yackavage '87 '02
Noel L. Yap '93
Andrew E. Zeger '65
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